The formula this page uses
1/R_total = 1/R₁ + 1/R₂ + 1/R₃ Iₙ = V / Rₙ I_total = ΣIₙ
Solve parallel circuit problems with clear steps, notation, and a final check.
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1/R_total = 1/R₁ + 1/R₂ + 1/R₃ Iₙ = V / Rₙ I_total = ΣIₙ
The circuit
Each extra branch is another road for current to take. More roads means less opposition overall, so adding a 1000 Ω branch beside a 10 Ω one still lowers the total slightly, from 10 Ω to 9.90 Ω.
So every socket gets the full 120 V or 230 V, and so switching off a lamp does not cut power to the fridge. The cost is that each appliance adds current, and enough of them together trip the breaker.
The one with the least resistance, because they all share the same voltage. In the three-branch example the 4 Ω path takes 6 A while the 12 Ω path takes only 2 A.
Only with exactly two resistors: R₁R₂/(R₁ + R₂). For 120 and 240 that gives 28800/360 = 80 Ω. For three or more, either use the reciprocal sum or combine two at a time.