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Parallel Circuit Calculator

Solve parallel circuit problems with clear steps, notation, and a final check.

Ω

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Parallel Circuit Calculator explained

The short version

  • In a parallel circuit every branch gets the full supply voltage.
  • The reciprocals of the resistances add, so the total is always smaller than the smallest branch.
  • Branch currents add up to the total current, which is why adding more appliances trips a breaker.

The formula this page uses

1/R_total = 1/R₁ + 1/R₂ + 1/R₃ Iₙ = V / Rₙ I_total = ΣIₙ

What each part means

SymbolWhat it means
V — Supply voltageThe same across every branch, in volts.
Rₙ — Branch resistanceIn ohms. Each branch is independent of the others.
R_total — Equivalent resistanceWhat a single replacement resistor would have to be. Always less than the smallest branch.
Iₙ — Branch currentV divided by that branch's resistance. Smaller resistance means bigger current.

Show your work: a full example

  1. The circuit120 Ω and 240 Ω in parallel across 12 V
  2. Add the reciprocals1/120 + 1/240 = 2/240 + 1/240 = 3/240
  3. Flip to get the totalR_total = 240/3 = 80 Ω
  4. Current in the 120 Ω branch12 ÷ 120 = 0.1 A
  5. Current in the 240 Ω branch12 ÷ 240 = 0.05 A
  6. Total current0.1 + 0.05 = 0.15 A
  7. Check against the equivalent resistance12 ÷ 80 = 0.15 A ✓, and total power is 12 × 0.15 = 1.8 W

A second, different case

  1. A different case: three branches on 24 V4 Ω, 6 Ω and 12 Ω in parallel
  2. Put the reciprocals over a common denominator1/4 + 1/6 + 1/12 = 3/12 + 2/12 + 1/12 = 6/12
  3. FlipR_total = 12/6 = 2 Ω, smaller than the 4 Ω branch
  4. Branch currents24/4 = 6 A, 24/6 = 4 A, 24/12 = 2 A
  5. Total6 + 4 + 2 = 12 A
  6. Check24 ÷ 2 = 12 A ✓
  7. Read itthe smallest resistor carries the most current, exactly half the total here
Copy-ready example

120 Ω and 240 Ω in parallel across 12 V

The circuit

Parallel combinations and their equivalent resistance

BranchesSum of reciprocalsR totalWhat to notice
100 Ω, 100 Ω0.0250 Ωtwo equal resistors halve
120 Ω, 240 Ω0.012580 Ωbelow the smaller branch, 120 Ω
100 Ω, 220 Ω0.01454568.75 Ωno whole-number answer, and that is normal
10 Ω, 1000 Ω0.1019.90 Ωa huge resistor barely changes the total
4 Ω, 6 Ω, 12 Ω0.52 Ωthree branches, still below the smallest
n identical Rn/RR/nthe general shortcut for equal branches

Three mistakes to check for

What students writeWhy it's wrongDo this instead
R_total = 120 + 240 = 360 ΩThat is the series rule. Extra parallel paths make it easier for current to flow, so the total must go down, not up.1/120 + 1/240 = 3/240, so R_total = 80 Ω.
1/R = 1/120 + 1/240 = 3/240, so R = 3/240 = 0.0125 ΩThe final flip was forgotten, leaving the reciprocal rather than the resistance.Invert: R = 240/3 = 80 Ω.
Using the product-over-sum shortcut on three resistorsR₁R₂/(R₁ + R₂) works for exactly two branches, not more.For 4, 6 and 12 Ω use the reciprocal sum, or apply product-over-sum twice.

Questions about the Parallel Circuit Calculator

Why is the total resistance smaller than any single branch?

Each extra branch is another road for current to take. More roads means less opposition overall, so adding a 1000 Ω branch beside a 10 Ω one still lowers the total slightly, from 10 Ω to 9.90 Ω.

Why is house wiring parallel rather than series?

So every socket gets the full 120 V or 230 V, and so switching off a lamp does not cut power to the fridge. The cost is that each appliance adds current, and enough of them together trip the breaker.

Which branch carries the most current?

The one with the least resistance, because they all share the same voltage. In the three-branch example the 4 Ω path takes 6 A while the 12 Ω path takes only 2 A.

When is the product-over-sum shortcut safe?

Only with exactly two resistors: R₁R₂/(R₁ + R₂). For 120 and 240 that gives 28800/360 = 80 Ω. For three or more, either use the reciprocal sum or combine two at a time.

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