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Zeros Of A Polynomial Calculator

Solve zeros of a polynomial problems with clear steps, notation, and a final check.

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Algebra

Zeros Of A Polynomial Calculator explained

The short version

  • A zero is an x value that makes the polynomial equal 0. On a graph it is where the curve meets the x-axis.
  • The rational root theorem builds a short list of candidates: factors of the constant over factors of the leading coefficient.
  • A degree-n polynomial has exactly n zeros once complex numbers are allowed, but only the real ones show up on the graph.

The formula this page uses

Any rational zero p/q of aₙxⁿ + … + a₀ has p dividing a₀ and q dividing aₙ

What each part means

SymbolWhat it means
a₀ — Constant termIts whole-number factors supply every possible numerator p.
aₙ — Leading coefficientIts factors supply every possible denominator q.
p/q — Candidate zeroTest each one. A remainder of 0 means it is a genuine zero.
multiplicity — How many times a zero repeatsA zero of multiplicity 2 touches the axis and bounces instead of crossing.

Show your work: a full example

  1. The polynomialf(x) = 2x³ − 3x² − 8x − 3
  2. Factors of the constant −3 give p±1, ±3
  3. Factors of the leading 2 give q±1, ±2
  4. Build the candidate list p/q±1, ±3, ±1/2, ±3/2
  5. Test x = −12(−1)³ − 3(−1)² − 8(−1) − 3 = −2 − 3 + 8 − 3 = 0, so x = −1 is a zero
  6. Divide out (x + 1) by synthetic divisioncoefficients 2, −3, −8, −3 reduce to 2, −5, −3 with remainder 0, so the quotient is 2x² − 5x − 3
  7. Factor the quotient2x² − 5x − 3 = (2x + 1)(x − 3), giving the remaining zeros x = −1/2 and x = 3

A second, different case

  1. A different case: complex zerosg(x) = x³ − x² + 4x − 4
  2. Group the terms in pairs(x³ − x²) + (4x − 4)
  3. Factor each pairx²(x − 1) + 4(x − 1)
  4. Pull out the shared bracket(x − 1)(x² + 4)
  5. First zerox − 1 = 0, so x = 1
  6. Second factorx² + 4 = 0, so x² = −4 and x = 2i or x = −2i
  7. Read the graphthree zeros in total but only one is real, so the curve crosses the x-axis exactly once
Copy-ready example

f(x) = 2x³ − 3x² − 8x − 3

The polynomial

Rational root candidates versus the zeros that actually appear

PolynomialConstant a₀Leading aₙCandidates p/qActual zeros
x² − 5x + 661±1, ±2, ±3, ±62 and 3
2x³ − 3x² − 8x − 3−32±1, ±3, ±1/2, ±3/2−1, −1/2, 3
x³ − x² + 4x − 4−41±1, ±2, ±41, 2i, −2i
3x² − 2−23±1, ±2, ±1/3, ±2/3±√(2/3) ≈ ±0.816, neither is rational

Three mistakes to check for

What students writeWhy it's wrongDo this instead
The candidates are just the factors of the constantThat is only true when the leading coefficient is 1. Otherwise every candidate also gets divided by a factor of aₙ.Include the halves: ±1/2 and ±3/2 belong on the list, and −1/2 turns out to be a real zero.
Degree 3, so the graph must cross the x-axis three timesComplex zeros are real solutions of the equation but they never appear as x-intercepts.x³ − x² + 4x − 4 has three zeros and exactly one crossing.
x² + 4 factors as (x + 2)(x − 2)That expands to x² − 4. A sum of squares does not factor over the real numbers.Over the complex numbers x² + 4 = (x + 2i)(x − 2i).

Questions about the Zeros Of A Polynomial Calculator

What is the difference between a zero, a root and an x-intercept?

A zero and a root are the same thing said about a function and about an equation. An x-intercept is the graph's version, and it only exists for real zeros, which is why 2i is a root of x³ − x² + 4x − 4 but never shows up on the picture.

Why does the rational root theorem never find √2?

Because it only searches fractions, and √2 cannot be written as one whole number over another. For x² − 2 the candidate list is ±1, ±2, all of which fail, which is itself proof that the zeros are irrational.

What does a repeated zero look like on a graph?

An even multiplicity makes the curve touch the axis and turn back, like y = (x − 3)² at x = 3. An odd multiplicity above 1 makes it flatten out as it passes through, like y = (x − 3)³.

How many zeros does a degree-n polynomial have?

Exactly n, counting complex zeros and counting repeats. That is the fundamental theorem of algebra. The degree-3 examples above each have three, even though one shows three crossings and the other shows one.

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