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← Precalculus formulas

Ellipse standard form: what it means and how to use it

Describe an axis-aligned ellipse centered at $(h,k)$.

Precalculus · Conics
$$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$$

Ellipse standard form is one of 3 conics formulas in the precalculus section of this library, and it is used at high school · ap level.

Why ellipse standard form works

Start with the unit circle x² + y² = 1 and stretch it, replacing x by x/a and y by y/b. Each denominator undoes its own stretch, so the equation still equals 1 while the picture has been pulled to width a and height b. Subtracting h and k slides the finished shape to its center.

What each symbol means

$a,b$ are positive semiaxis lengths; the larger denominator gives the major axis.

Ellipse standard form: when it holds

$a,b>0$; if $a>b$, focal distance satisfies $c^2=a^2-b^2$.

When it stops applying

The right side must be exactly 1, so an equation like x²/9 + y²/4 = 36 has to be divided through before you can read anything off. The form also assumes the axes are horizontal and vertical; a tilted ellipse carries an xy term this shape cannot show.

Ellipse standard form: a worked example

$x^2/25+y^2/9=1$ has vertices $(\pm5,0)$ and foci $(\pm4,0)$.

The mistake to avoid

What people do: Students assume a is always the larger number and place the major axis horizontally every time.

Why it goes wrong: The letters do not decide the shape; the denominators do. In x²/9 + y²/25 = 1 the bigger denominator sits under y, so the ellipse is taller than it is wide.

Do this instead: Compare the two denominators and put the major axis under the larger one. Here the semi-major length is 5 along the y-axis, the semi-minor is 3, and the foci are at (0, ±4) since 25 − 9 = 16.

Ellipse standard form: step by step

  1. Name the unknown, and the unit the answer has to come out in.
  2. Match the symbols to your values. $a,b$ are positive semiaxis lengths; the larger denominator gives the major axis.
  3. Check the conditions before substituting. $a,b>0$; if $a>b$, focal distance satisfies $c^2=a^2-b^2$.
  4. Substitute, keep exact values to the last line, then test the sign, size, and unit against a rough estimate — the check that catches most precalculus slips.

Where this formula fits

Subject
Precalculus formulas — 10 entries in this library
Topic
Conics
Level
High school · AP

Formulas are easiest to keep when they sit inside a method rather than on a list. Use the links below to see where ellipse standard form comes from, to check a calculation against a tool, and to practise it until you can recall it without looking.

Questions about ellipse standard form

How do I find the foci?

Subtract the smaller denominator from the larger and take the square root to get c, then move c units from the center along the major axis. For x²/25 + y²/9 = 1 that gives c = 4 and foci at (±4, 0).

What if the two denominators are equal?

You have a circle, which is an ellipse whose two axes match. Then c = 0 and both foci collapse onto the center, which is why a circle has no visible focal points.

What does eccentricity measure?

How stretched the ellipse is, computed as c divided by the semi-major length. A value near 0 looks circular, and a value near 1 is long and thin, which is how comet orbits are described.

Why is the sum of the two focal distances constant?

That is the defining property, and it is the reason the gardener's trick works: pin a loop of string on two nails, pull it taut with a pencil, and the curve you trace is an ellipse.

Stuck on a problem?

Work a ellipse standard form problem step by step

Type your own problem, or upload a photo of it. You get the method, the answer, and a check you can repeat yourself.