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Standard Form Polynomial Calculator

Solve standard form polynomial problems with clear steps, notation, and a final check.

Calculate without using AI.

Evaluate the governing formula locally in your browser. Define each known quantity once, then change values to test another case instantly.

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Algebra

Standard Form Polynomial Calculator explained

The short version

  • Standard form lists a polynomial's terms from the highest power down to the constant.
  • Once it is sorted, the degree, the leading coefficient and the y-intercept are all sitting where you can read them.
  • Getting there means expanding every bracket and combining every pair of like terms first.

The formula this page uses

aₙxⁿ + aₙ₋₁xⁿ⁻¹ + … + a₁x + a₀, with the exponents strictly decreasing

What each part means

SymbolWhat it means
aₙ — Leading coefficientThe number on the highest-power term. Its sign controls the right-hand end of the graph.
n — DegreeThe exponent on the first term once sorted.
a₀ — Constant termThe last term, with no variable. It equals the y-intercept.
aᵢ — Missing coefficientsA gap counts as 0, which matters when you set up synthetic division.

Show your work: a full example

  1. The expression as given7 − 2x³ + x − 5x²
  2. Tag each term with its degree7 is degree 0, −2x³ is degree 3, x is degree 1, −5x² is degree 2
  3. Sort from highest degree down−2x³ − 5x² + x + 7
  4. Read the degree3
  5. Read the leading coefficient with its sign−2
  6. Read the y-interceptthe constant 7, so the curve passes (0, 7)
  7. Predict the endsodd degree with a negative lead, so it rises on the left and falls on the right

A second, different case

  1. A different case: expand a product first(2x − 3)(x² + 4x − 1)
  2. Multiply 2x through2x³ + 8x² − 2x
  3. Multiply −3 through−3x² − 12x + 3
  4. Write everything together2x³ + 8x² − 2x − 3x² − 12x + 3
  5. Combine the x² terms8x² − 3x² = 5x²
  6. Combine the x terms−2x − 12x = −14x
  7. Standard form2x³ + 5x² − 14x + 3, and testing x = 1 gives 2 + 5 − 14 + 3 = −4, matching (2 − 3)(1 + 4 − 1) = −4
Copy-ready example

7 − 2x³ + x − 5x²

The expression as given

Three forms of the same parabola, y = x² − 6x + 5

FormTemplateWritten outWhat you can read straight off
Standardax² + bx + cy = x² − 6x + 5y-intercept 5, degree 2, leading coefficient 1
Vertexa(x − h)² + ky = (x − 3)² − 4vertex (3, −4) and the axis of symmetry x = 3
Factoreda(x − r₁)(x − r₂)y = (x − 1)(x − 5)the two x-intercepts, x = 1 and x = 5
Standard, cubicax³ + bx² + cx + dy = 2x³ + 5x² − 14x + 3y-intercept 3, degree 3, rises to the right

Three mistakes to check for

What students writeWhy it's wrongDo this instead
7 − 2x³ + x − 5x² is already in standard formStandard form is ordered by exponent, not by whichever term happened to be written first.Sort it: −2x³ − 5x² + x + 7.
The leading coefficient of −2x³ − 5x² + x + 7 is 2The minus sign belongs to the coefficient and decides the end behaviour.It is −2, so the graph falls on the right.
(2x − 3)(x² + 4x − 1) = 2x³ + 3Only the first pair and the last pair were multiplied, so four products went missing.Every term meets every term: 2x³ + 5x² − 14x + 3.

Questions about the Standard Form Polynomial Calculator

Why does standard form matter if the polynomial is the same either way?

Because three facts become free to read: the first term gives degree and end behaviour, and the last gives the y-intercept. Synthetic division, long division and most graphing routines also assume the terms arrive in that order.

Can standard form have fractions or decimals in it?

Yes. ½x² − 0.4x + 3 is perfectly standard, because the rule only constrains the order of the exponents. Many teachers ask you to clear fractions afterwards, but that is a tidiness preference, not a definition.

What do I do when two terms have the same power?

Add their coefficients into a single term, because standard form allows exactly one term per exponent. 8x² − 3x² becomes 5x², and if they cancel to zero the term disappears and the degree may drop.

What happens to a power that is missing?

Its coefficient is 0 and the term is simply not written. That is fine on paper but not in synthetic division, where you must insert a 0 placeholder or every later column shifts and the answer comes out wrong.

Where to go next

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