The formula this page uses
f′(x) = lim[h→0] (f(x + h) − f(x)) / h ∫ₐᵇ f(x) dx = F(b) − F(a)
Explore derivatives, definite integrals, limits, roots, Taylor approximations, arc length, and average value with numerical working and a live graph.
f′(x) = lim[h→0] (f(x + h) − f(x)) / h ∫ₐᵇ f(x) dx = F(b) − F(a)
Start with the function
Both descriptions fit. Choose differentiation, integration, limits, roots, Taylor polynomials, or arc length, then enter the function and any required values. The calculus solver returns the result with the mathematical steps; for an unstructured word problem where the method is not yet clear, use the AI math solver instead.
Probably not. A definite integral adds signed area, so any stretch where the curve dips below the x-axis counts as negative. If the question asks for total area instead, split the interval at each x-intercept and add the absolute values.
Because differentiating kills constants. x², x² + 7 and x² − 100 all have derivative 2x, so reversing the process cannot tell which one you started from. The C carries that missing information.
f(2) is the height of the curve at x = 2; here it is 2³ − 4(2) = 0. f′(2) is the steepness there, which is 8. A curve can sit at height zero while climbing steeply, and this function does exactly that.
Whenever the thing being raised to a power is not just x. (x³ − 4x)⁵ needs the chain rule: differentiate the outside to 5(x³ − 4x)⁴ and then multiply by the inside derivative 3x² − 4.
Use numerical results to explore and verify. For a proof or exact symbolic derivation, follow the linked step-by-step solver and check its assumptions.
Estimate local rate of change with centered finite differences and visualize the tangent line.
Use adaptive Simpson integration to estimate signed accumulated area over a finite interval.
Compare values approaching from both sides so one-sided disagreement remains visible.
Approximate a function near a center and compare the polynomial with the original curve.
Numerical-method note: Decimal results are estimates. Discontinuities, oscillation, very large values, and poorly scaled inputs can require symbolic analysis or tighter assumptions.
A calculator confirms an answer. Working the method yourself is what makes the next problem faster.